Integrand size = 24, antiderivative size = 65 \[ \int (d+e x)^2 \left (a^2+2 a b x+b^2 x^2\right ) \, dx=\frac {(b d-a e)^2 (a+b x)^3}{3 b^3}+\frac {e (b d-a e) (a+b x)^4}{2 b^3}+\frac {e^2 (a+b x)^5}{5 b^3} \]
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Time = 0.03 (sec) , antiderivative size = 65, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {27, 45} \[ \int (d+e x)^2 \left (a^2+2 a b x+b^2 x^2\right ) \, dx=\frac {e (a+b x)^4 (b d-a e)}{2 b^3}+\frac {(a+b x)^3 (b d-a e)^2}{3 b^3}+\frac {e^2 (a+b x)^5}{5 b^3} \]
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Rule 27
Rule 45
Rubi steps \begin{align*} \text {integral}& = \int (a+b x)^2 (d+e x)^2 \, dx \\ & = \int \left (\frac {(b d-a e)^2 (a+b x)^2}{b^2}+\frac {2 e (b d-a e) (a+b x)^3}{b^2}+\frac {e^2 (a+b x)^4}{b^2}\right ) \, dx \\ & = \frac {(b d-a e)^2 (a+b x)^3}{3 b^3}+\frac {e (b d-a e) (a+b x)^4}{2 b^3}+\frac {e^2 (a+b x)^5}{5 b^3} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.22 \[ \int (d+e x)^2 \left (a^2+2 a b x+b^2 x^2\right ) \, dx=a^2 d^2 x+a d (b d+a e) x^2+\frac {1}{3} \left (b^2 d^2+4 a b d e+a^2 e^2\right ) x^3+\frac {1}{2} b e (b d+a e) x^4+\frac {1}{5} b^2 e^2 x^5 \]
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Time = 2.07 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.29
method | result | size |
norman | \(\frac {b^{2} e^{2} x^{5}}{5}+\left (\frac {1}{2} a b \,e^{2}+\frac {1}{2} b^{2} d e \right ) x^{4}+\left (\frac {1}{3} a^{2} e^{2}+\frac {4}{3} a b d e +\frac {1}{3} b^{2} d^{2}\right ) x^{3}+\left (a^{2} d e +a b \,d^{2}\right ) x^{2}+a^{2} d^{2} x\) | \(84\) |
default | \(\frac {b^{2} e^{2} x^{5}}{5}+\frac {\left (2 a b \,e^{2}+2 b^{2} d e \right ) x^{4}}{4}+\frac {\left (a^{2} e^{2}+4 a b d e +b^{2} d^{2}\right ) x^{3}}{3}+\frac {\left (2 a^{2} d e +2 a b \,d^{2}\right ) x^{2}}{2}+a^{2} d^{2} x\) | \(87\) |
risch | \(\frac {1}{5} b^{2} e^{2} x^{5}+\frac {1}{2} x^{4} a b \,e^{2}+\frac {1}{2} x^{4} b^{2} d e +\frac {1}{3} x^{3} a^{2} e^{2}+\frac {4}{3} x^{3} a b d e +\frac {1}{3} d^{2} x^{3} b^{2}+a^{2} d e \,x^{2}+x^{2} a b \,d^{2}+a^{2} d^{2} x\) | \(90\) |
parallelrisch | \(\frac {1}{5} b^{2} e^{2} x^{5}+\frac {1}{2} x^{4} a b \,e^{2}+\frac {1}{2} x^{4} b^{2} d e +\frac {1}{3} x^{3} a^{2} e^{2}+\frac {4}{3} x^{3} a b d e +\frac {1}{3} d^{2} x^{3} b^{2}+a^{2} d e \,x^{2}+x^{2} a b \,d^{2}+a^{2} d^{2} x\) | \(90\) |
gosper | \(\frac {x \left (6 b^{2} e^{2} x^{4}+15 x^{3} a b \,e^{2}+15 x^{3} b^{2} d e +10 x^{2} a^{2} e^{2}+40 x^{2} a b d e +10 d^{2} x^{2} b^{2}+30 a^{2} d e x +30 x a b \,d^{2}+30 a^{2} d^{2}\right )}{30}\) | \(91\) |
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Time = 0.29 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.25 \[ \int (d+e x)^2 \left (a^2+2 a b x+b^2 x^2\right ) \, dx=\frac {1}{5} \, b^{2} e^{2} x^{5} + a^{2} d^{2} x + \frac {1}{2} \, {\left (b^{2} d e + a b e^{2}\right )} x^{4} + \frac {1}{3} \, {\left (b^{2} d^{2} + 4 \, a b d e + a^{2} e^{2}\right )} x^{3} + {\left (a b d^{2} + a^{2} d e\right )} x^{2} \]
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Time = 0.03 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.34 \[ \int (d+e x)^2 \left (a^2+2 a b x+b^2 x^2\right ) \, dx=a^{2} d^{2} x + \frac {b^{2} e^{2} x^{5}}{5} + x^{4} \left (\frac {a b e^{2}}{2} + \frac {b^{2} d e}{2}\right ) + x^{3} \left (\frac {a^{2} e^{2}}{3} + \frac {4 a b d e}{3} + \frac {b^{2} d^{2}}{3}\right ) + x^{2} \left (a^{2} d e + a b d^{2}\right ) \]
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Time = 0.20 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.25 \[ \int (d+e x)^2 \left (a^2+2 a b x+b^2 x^2\right ) \, dx=\frac {1}{5} \, b^{2} e^{2} x^{5} + a^{2} d^{2} x + \frac {1}{2} \, {\left (b^{2} d e + a b e^{2}\right )} x^{4} + \frac {1}{3} \, {\left (b^{2} d^{2} + 4 \, a b d e + a^{2} e^{2}\right )} x^{3} + {\left (a b d^{2} + a^{2} d e\right )} x^{2} \]
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Time = 0.25 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.37 \[ \int (d+e x)^2 \left (a^2+2 a b x+b^2 x^2\right ) \, dx=\frac {1}{5} \, b^{2} e^{2} x^{5} + \frac {1}{2} \, b^{2} d e x^{4} + \frac {1}{2} \, a b e^{2} x^{4} + \frac {1}{3} \, b^{2} d^{2} x^{3} + \frac {4}{3} \, a b d e x^{3} + \frac {1}{3} \, a^{2} e^{2} x^{3} + a b d^{2} x^{2} + a^{2} d e x^{2} + a^{2} d^{2} x \]
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Time = 0.05 (sec) , antiderivative size = 74, normalized size of antiderivative = 1.14 \[ \int (d+e x)^2 \left (a^2+2 a b x+b^2 x^2\right ) \, dx=x^3\,\left (\frac {a^2\,e^2}{3}+\frac {4\,a\,b\,d\,e}{3}+\frac {b^2\,d^2}{3}\right )+a^2\,d^2\,x+\frac {b^2\,e^2\,x^5}{5}+a\,d\,x^2\,\left (a\,e+b\,d\right )+\frac {b\,e\,x^4\,\left (a\,e+b\,d\right )}{2} \]
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